C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t trong ch\u01a1i l\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc l\u00e0 m\u1ed9t trong nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p kh\u00e1 \u0111\u01b0\u1ee3c \u01b0a chu\u1ed9ng b\u1edfi c\u00e1c anh em ch\u01a1i chuy\u00ean nghi\u1ec7p, v\u1ec1 c\u01a1 b\u1ea3n th\u00ec khi b\u1eaft t\u1ed5ng \u0111\u1ec1 c\u0169ng \u0111\u01b0\u1ee3c chia ra l\u00e0m 2 d\u1ea1ng l\u00e0 \u0111\u01a1n gi\u1ea3n v\u00e0 c\u1ea7n \u0111\u1ea7u \u00f3c t\u00ednh to\u00e1n k\u1ef9 l\u01b0\u1ee1ng.<\/p>\n
Trong n\u1ed9i dung n\u00e0y, ch\u00fang t\u00f4i s\u1ebd chia s\u1ebb cho b\u1ea1n 6 ph\u01b0\u01a1ng ph\u00e1p b\u1eaft c\u00e1c t\u1ed5ng trong x\u1ed5 s\u1ed1 \u0111\u00e3 \u0111\u01b0\u1ee3c ki\u1ec3m ch\u1ee9ng l\u00e0 s\u1ebd gi\u00fap cho anh em n\u00e2ng cao x\u00e1c su\u1ea5t tr\u00fang x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc l\u00ean cao nh\u1ea5t.<\/p>\n
C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t hi\u1ec7u qu\u1ea3 b\u1eb1ng c\u1ed9ng quy lu\u1eadt Pascal<\/h2>\n
C\u00e1ch n\u00e0y \u0111\u01b0\u1ee3c th\u1ef1c hi\u1ec7n nh\u01b0 sau:<\/strong><\/p>\n C\u00e1ch n\u00e0y \u0111\u01b0\u1ee3c th\u1ef1c hi\u1ec7n nh\u01b0 sau: Tr\u01b0\u1edbc h\u1ebft x\u00e1c \u0111\u1ecbnh m\u1ed1c h\u00f4m b\u1eaft \u0111\u1ea7u t\u00ednh ch\u00fang ta c\u00f3: Coi gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y th\u1ee9 nh\u1ea5t l\u00e0 AB, \u0111\u1eb7c bi\u1ec7t n\u1ed5 ng\u00e0y th\u1ee9 hai l\u00e0 CD.<\/p>\n Ta c\u00f3 A + B = E; C + D = F.<\/strong><\/p>\n X\u00e9t c\u00e1c gi\u1ea3 \u0111\u1ecbnh x\u1ea3y ra nh\u01b0 sau:<\/strong><\/p>\n + tr\u01b0\u1eddng h\u1ee3p 1: N\u1ebfu E < 10, F < 10 l\u1ea5y 10 \u2013 E = X, 10 \u2013 F = Y. Ch\u01a1i XY cho l\u00f4 ng\u00e0y th\u1ee9 3.<\/p>\n + tr\u01b0\u1eddng h\u1ee3p 2: N\u1ebfu E > 10, F < 10 l\u1ea5y 20 \u2013 E = X, 10 \u2013 F = Y, \u0111\u00e1nh l\u00f4 XY ng\u00e0y th\u1ee9 3.<\/p>\n + tr\u01b0\u1eddng h\u1ee3p 3: N\u1ebfu E > 10, F > 10 l\u1ea5y 20 \u2013 E = X, 20 \u2013 F = Y, \u0111\u00e1nh l\u00f4 ng\u00e0y th\u1ee9 3 l\u00e0 XY.<\/p>\n + gi\u1ea3 \u0111\u1ecbnh 4: N\u1ebfu E < 10, F > 10. Ch\u00fang ta l\u1ea5y hi\u1ec7u 10 \u2013 E = X, 20 \u2013 F = Y, ng\u00e0y th\u1ee9 3 c\u01b0\u1ee3c l\u00e0 YX.<\/p>\n + gi\u1ea3 \u0111\u1ecbnh 5: E = 0 ho\u1eb7c 10, F = 0 ho\u1eb7c 10 th\u00ec X, Y \u0111\u1ec1u l\u00e0 0.<\/p>\n C\u1ea7u n\u00e0y c\u00f3 th\u1ec3 \u0111\u1eb7t c\u01b0\u1ee3c li\u00ean ti\u1ebfp trong 3 \u2013 4 ng\u00e0y.<\/p>\n N\u1ebfu h\u00f4m sau c\u01b0\u1ee3c m\u00e0 kh\u00f4ng ra th\u00ec ngh\u1ec9 1 ng\u00e0y, nh\u01b0ng c\u1ea7u l\u1ea1i ra \u0111\u00fang h\u00f4m ngh\u1ec9 th\u00ec b\u1ecf c\u1ea7u lu\u00f4n, c\u00f2n n\u1ebfu v\u1eabn kh\u00f4ng v\u1ec1 th\u00ec ng\u00e0y mai s\u1ebd v\u1ec1.<\/p>\n Gi\u1ea3 \u0111\u1ecbnh n\u1ed5 l\u1ed9n th\u00ec ngh\u1ec9 3, 4 ng\u00e0y r\u1ed3i m\u1edbi c\u01b0\u1ee3c ti\u1ebfp t\u1ee5c c\u1ea7u n\u00e0y.<\/p>\n N\u1ebfu c\u1ea7u n\u00e0y kh\u00f4ng ra trong 5, 6 ng\u00e0y th\u00ec ngh\u1ec9 h\u00f4m th\u1ee9 7 ti\u1ebfp \u0111\u00f3 ch\u01a1i 3 ng\u00e0y ti\u1ebfp, th\u1ea5y h\u00f4m th\u1ee9 7 ra th\u00ec ch\u01a1i c\u1ea7u n\u00e0y v\u00e0o ng\u00e0y th\u1ee9 8.<\/p>\n <\/p>\n C\u00e1ch n\u00e0y s\u1eed d\u1ee5ng nh\u01b0 sau: D\u00f9ng s\u1ed1 \u0111\u1ea7u ti\u00ean c\u1ee7a gi\u1ea3i \u0111\u1ec1 h\u00f4m th\u1ee9 2 \u0111\u1ec3 l\u00e0m t\u1ed5ng chu\u1ea9n nu\u00f4i cho c\u1ea3 7 ng\u00e0y. T\u1eeb \u0111\u00f3 ch\u00fang ta l\u1eadp d\u00e0n \u0111\u1ec1 c\u1ee7a t\u1ed5ng n\u00e0y \u0111\u1ec3 nu\u00f4i l\u00f4, t\u1ef7 l\u1ec7 th\u1eafng l\u00e0 t\u01b0\u01a1ng \u0111\u1ed1i cao.<\/p>\n Ch\u00fang ta c\u00f3 th\u1ee9 2 ng\u00e0y 17\/7\/2024 gi\u1ea3i \u0111u\u00f4i ra 05488, l\u1ea5y 0 l\u00e0m t\u1ed5ng chu\u1ea9n ch\u00fang ta c\u00f3 d\u00e0n sau:<\/p>\n 00, 191, 282, 373, 464, 55.<\/p>\n Ch\u00fang ta c\u00f3 \u0111\u01b0\u1ee3c k\u1ebft q\u1ee7a:<\/strong><\/p>\n Theo kinh nghi\u1ec7m s\u1ed1 \u0111\u1ec1<\/strong> c\u1ee7a nhi\u1ec1u anh em t\u1eebng ch\u01a1i tr\u01b0\u1edbc \u0111\u00e2y th\u00ec \u0111\u00e3 ch\u1ee9ng minh r\u1eb1ng khi t\u1ed5ng c\u1ee7a gi\u1ea3i \u0111u\u00f4i ra r\u01a1i v\u00e0o c\u00e1c tr\u01b0\u1eddng h\u1ee3p sau \u0111\u00e2y th\u00ec anh em c\u00f3 th\u1ec3 ch\u1ecdn d\u00e0n t\u1ed5ng t\u01b0\u01a1ng \u1ee9ng:<\/p>\n T\u1eeb \u0111\u00f3, b\u1ea1n c\u00f3 th\u1ec3 \u0111\u00e1nh d\u00e0n \u0111\u1ec1 t\u01b0\u01a1ng \u1ee9ng, v\u00ed d\u1ee5 nh\u01b0 t\u1ed5ng 5 c\u00f3 d\u00e0n 050, 141, 232.<\/p>\n Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y g\u1ed3m 2 c\u00e1ch c\u1ee5 th\u1ec3 sau:<\/p>\n C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t trong l\u00f4 \u0111\u1ec1, s\u1ed1 \u0111u\u00f4i mb hay hi\u1ec7n nay ch\u00fang t\u00f4i \u0111\u00e3 chia s\u1ebb tr\u00ean \u0111\u00e2y s\u1ebd gi\u00fap b\u1ea1n c\u00f3 \u0111\u01b0\u1ee3c nh\u1eefng c\u00e1ch b\u1eaft t\u1ed5ng chu\u1ea9n v\u1edbi x\u00e1c su\u1ea5t cao nh\u1ea5t, \u0111\u1ec1 t\u00ecm \u0111\u01b0\u1ee3c nhi\u1ec1u c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc h\u01a1n, h\u00e3y truy c\u1eadp nh\u00e0 c\u00e1i ch\u00fang t\u00f4i<\/strong> h\u00e0ng ng\u00e0y \u0111\u1ec3 c\u00f3 th\u1ec3 xem th\u00eam nhi\u1ec1u c\u00e1ch v\u00e0 kinh nghi\u1ec7m h\u1eefu \u00edch kh\u00e1c. \u0110\u1eb7c bi\u1ec7t nh\u1eefng ai \u0111ang quan t\u00e2m t\u1edbi l\u00f4 \u0111\u1ec1 online th\u00ec c\u00f3 th\u1ec3 \u0111\u0103ng k\u00fd t\u1ea1i nh\u00e0 c\u00e1i \u0111\u1ec3 tr\u1ea3i nghi\u1ec7m t\u1ef7 l\u1ec7 tr\u00fang th\u01b0\u1edfng 1 \u0103n 99 nh\u00e9. B\u1ea5m n\u00fat \u201c\u0110\u0102NG K\u00dd NGAY\u201d \u0111\u1ec3 tham gia!<\/p>\n CH\u00daC C\u00c1C B\u1ea0N TH\u00c0NH C\u00d4NG!<\/strong><\/p>\n<\/div>\n<\/div>\n<\/article>\n<\/div>\n<\/div>\n<\/div>\n h\u00e3y soi c\u1ea7u mi\u1ec1n b\u1eafc si\u00eau chu\u1ea9n h\u00f4m nay c\u00f9ng ch\u00fang t\u00f4i. anh ch\u1ecb l\u01b0\u1edbt xu\u1ed1ng d\u01b0\u1edbi xem d\u1ecbch v\u1ee5 chu\u1ea9n x\u00e1c h\u00f4m nay<\/span><\/p>\n <\/p>\n\n
C\u00e1ch b\u1eaft t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t t\u00ednh l\u00f4<\/h2>\n
C\u00e1ch b\u1eaft XSMB th\u00f4ng qua s\u1ed1 \u0111\u1ea7u ti\u00ean gi\u1ea3i \u0111\u1eb7c bi\u1ec7t th\u1ee9 2<\/h2>\n
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C\u00e1ch b\u1eaft t\u1ed5ng l\u00f4 \u0111\u1ec1 b\u1eb1ng ph\u01b0\u01a1ng ph\u00e1p b\u1ea1c nh\u1edb<\/h2>\n
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C\u00e1ch b\u1eaft s\u1ed1 \u0111\u1ec1, l\u00f4 \u0111\u1ec1 d\u1ef1a v\u00e0o t\u1ed5ng \u0111\u1eb7c bi\u1ec7t<\/h2>\n
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